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The eletrostaic force on a small sphere of charges 0.4mu Cdue to another small sphere of charge 0. 8 mu Cin air 0.2 N. What is the distance between the two spheres? (b)What is the force on the second sphere dueto the first? |
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Answer» Solution :Here ` q_1 =0.4 muC= 4XX 10^(-7) C,q_2 =0.8 muC =-8xx10 ^(-7)C ` and ATTRACTIVE FORCE in air F =0.2 N (a)Fromthe relation `F= 9xx 10 ^(9) (q_1q_2)/( r^(2)) , `we have `r= [( (9xx 10 ^(9)) (q_1q_2))/( F) ]^(1//2)=[( 9xx10^(9)(4xx 10^(-7)XX(8xx10^(-7))))/(0.2)]^(1//2) = 0.12 m or 12 cm ` (b)`|oversetto (F_21) |=|oversetto (F_12) | =0.2 N` (attractive) |
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