The emf of the cell reaction `Zn(s) +Cu^(2+) (aq) rarr Zn^(2+) (aQ) +Cu(s)` is `1.1V`. Calculate the free enegry change for the reaction. If the enthalpy of the reaction is `-216.7 kJ mol^(-1)`, calculate the entropy change for the reaction.

The emf of the cell reaction `Zn(s) +Cu^(2+) (aq) rarr Zn^(2+) (aQ) +C

1.	The emf of the cell reaction `Zn(s) +Cu^(2+) (aq) rarr Zn^(2+) (aQ) +Cu(s)` is `1.1V`. Calculate the free enegry change for the reaction. If the enthalpy of the reaction is `-216.7 kJ mol^(-1)`, calculate the entropy change for the reaction.
Answer» `-DeltaG^(@)=nxxFxxE^(@)=2xx96500xx1.1=212.3kJ` `DeltaG^(@)=-212.3kJ" "mol^(-1)` `DeltaG^(@)=DeltaH^(@)-TDeltaS^(@)` `DeltaS^(@)=(DeltaH^(@)-DeltaG^(@))/(T)=(-216.7-(-212.3))/(298)` `=-0.01476" kJ "K^(-1)mol^(-1)` `=-14.76" J "K^(-1)mol^(-1)`.

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The emf of the cell reaction `Zn(s) +Cu^(2+) (aq) rarr Zn^(2+) (aQ) +Cu(s)` is `1.1V`. Calculate the free enegry change for the reaction. If the enthalpy of the reaction is `-216.7 kJ mol^(-1)`, calculate the entropy change for the reaction.

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