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the end of the diameter of a circle have the coordinates (0,3) and (-5,6). PQ is another diameter where What's coordinates(-1,-2) find the coordinates of P and the radius of circle. |
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Answer» -STEP EXPLANATION:Let AB be a diameter of the circle having its CENTRE at C(1, -3) such that the coordinates of one end A are (4, -1).Let the coordinates of B be (x,y).Since C is the mid-point of AB. Therefore,the coordinates of C are( 2x+4 , 2y−1 ).But, the coordinates of C are GIVEN to be (1,-3).∴ 2x+4 =1and 2y−1 =−3⇒x+4=2andy−1=−6⇒x=−2andy=−5Hence,the coordinates of B are (-2, -5). |
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