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| 1. |
The energy density at a point in a medium of dielectric constant 8 is 26.55xx10^6J//m Calculate the field intensity at that point. |
| Answer» SOLUTION :k=8 ENERGY DENSITY `=26.55xx10^-6J//m^3epsilon_0=8.85xx10^-12F//m.` Energy density `1/2epsilon_0kE^2E=SQRT((2("energydensity"))/(epsilon_0k)=sqrt((2xx26.55xx10^-6)/(8.85xx10^-12xx8))=sqrt(3/4xx10^6)sqrt3/2xx10^3=8.66xx10^2N//C.` | |