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The energy levels of a hypotherical one electron atom are shown in figure Find the excitation potential for the state `n = 3`.A. `14.64 eV`B. `9.93 eV`C. `12.52 eV`D. `10.04 eV` |
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Answer» Correct Answer - C The excitation energy for the `n = 3` state is `Delta E = E_(3) - E_(1) = 15.6 - 3.08 = 12.52 eV` Excitation potential `= 12.52 V` |
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