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The energy of a photon of wavelength `lambda` is given byA. `hclambda`B. `(hlambda)/(c )`C. `(lambda)/(hc)`D. `(hc)/(lambda)` |
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Answer» Correct Answer - d `(hc)/(lambda)` Energy of a photon, `E = hv = (hc)/(lambda)` |
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