1.

The energy of activation for a reaction is 100 KJ mol^(-1). The peresence of a catalyst lowers the energy of activation by 75%. What will be the effect on the rate of reaction at 20^(@)C, other things being equal?

Answer»

SOLUTION :`2.35xx10^13` TIMES
LOG`K_2/K_1=(E_a-E_p)/(2.303RT) RARR log K_2/K_1=(75xx10^3)/(2.303xx8.314xx293)`


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