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The energy of an electron in an excited hydrogen atom is -3.4 eV The corresponding excited state (n) is

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Solution :`E_(n)=(-2pi mk^(2) E^(4) z^(2))/(n^(2)h^(2))`
For `H_(2) z=1`
`E_(n)=(-2pi nk^(2)e^(4))/(n^(2)h^(2))`
`=-(2pi mk^(2)e^(4))/(ch^(3)) (ch)/(n^(2))=-(R ch)/(n^(2))`
`n^(2)=-(Rch)/(E)=4.012 "R=Rydberg.s CONST."`
`rArr n=2 =1.09737 XX 10^(7)`


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