1.

The energy of an electron in hydrogen atom is -3.4 eV, then itsangular momentum is ......

Answer»

`2.1xx10^(-34)JS`
`2.1xx10^(-20)Js`
`4xx10^(-20)Js`
`4xx10^(-34)Js`

Solution :`E_(n)=-(13.6)/(n^(2))`
`:.-3.4=-(13.6)/(n^(2))`
`:.n^(2)=(13.6)/(3.4)=4`
`:.n=2`
`:.` ANGULAR momentum in `n^(th)` ORBIT,
`L_(n)=(nh)/(2pi),n=2`
`L_(2)=(2h)/(2pi)=(h)/(PI)=(6.625xx10^(-34))/(3.14)=2.109xx10^(-34)`
`:.L_(2)~~2.5xx10^(-34)Js`


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