The energy of electron in first Bohr's orbit of Hatom is -13.6 ev. Wha

1.	The energy of electron in first Bohr's orbit of Hatom is -13.6 ev. What will be its potentialenergy in n 4th orbit -(A) 13.6 eV(C) -0.85 ev(B) -3.4 ev(D) -1.70 eV
Answer» potential energy is 2 times that of the total energy and total energy on nth orbital is given by E = -13.6z²/n² eV => E = -13.61/(4)² = -0.85eV but P.E = 2 T.E = -1.70 eV so, option D

The energy of electron in first Bohr's orbit of Hatom is -13.6 ev. What will be its potentialenergy in n 4th orbit -(A) 13.6 eV(C) -0.85 ev(B) -3.4 ev(D) -1.70 eV

Answer»

potential energy is 2 times that of the total energy

and total energy on nth orbital is given by

E = -13.6*z²/n² eV => E = -13.6*1/(4)² = -0.85eV

but P.E = 2 T.E = -1.70 eV

so, option D