1.

The energy of electron in the nth orbit of hydrogen atom is expressed as E_m=(-13.6)/(n^(2)) eV. The shortest and longest wavelength of Lyman series will be

Answer»

910Å, 1213Å
5463Å, 7858Å
1315Å, 1530Å
None of these

Solution :`1/(lambda_("max"))=R[(1)/((1)^(2))-(1)/((2)^(2))] rArr lambda_("max")=(4)/(3R) approx 1213Å`
`and (1)/(lambda_("min"))=R[(1)/((1)^(2))-(1)/OO] rArr lambda_("min")=(1)/(R) approx 910Å`


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