1.

The energy of the ground state of hydrogen is -13.6eV. The energy of the first excited state is

Answer»

`-27.2` eV
`-52.4` eV
`-3.4` eV
`-6.8` eV

Solution :For the first excited STATE, N = 2
`therefore E_(2) = (E_(1))/(E_(2)) = (-13.6 eV)/(4) = -3.4 eV`


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