1.

The energy of the hydrogen atom in its ground state is -13.6 eV. Determine the energy of the energy level whose quantum number is 2.

Answer»



Solution :Energy of hydrogen atom in NTH orbit is
`E=-(13.6)/(n^(2))EV`
For IST excited STATE, `n=2`
`E=-(13.6)/(4)=-3.4 eV`


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