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The energy required to excition an electron from `n=2` to `n=3` energy state is `47.2eV`. The charge number of the nucleus, around which the electrons revolving will beA. `5`B. `10`C. `15`D. `20` |
Answer» Correct Answer - A `E=E_(3)-E_(2)=(13.6Z^(2))/4-(13.6Z^(2))/9=47.2` ` Rightarrow Z=?` |
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