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The energyof a photonof sodiumlight ( lamda = 589nm)equalto thebandgapof asemiconducingmaterial . Findtheminimum energyE requiredto createahole-electronpair. |
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Answer» Solution : The energy of the photon in eV =`( 12400 )/(lamda)` WAVELENGTH of photon = 589 NM `= 5890 A^0` `=(12400)/( 5890) = 2.1eV ` Thus the band gap is 2.1 eV. This is also the MINIMUM energy E required to push an ELECTRON from the valence band into the conduction band. Hence, the minimum energy required to create a hole-electron pair is 2.1eV. |
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