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The energyof a photonof sodiumlight ( lamda = 589nm)equalto thebandgapof asemiconducingmaterial . Find thevalueofE /kTat a temperatureof300 K. |
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Answer» Solution :At T= 300 K, KT=(`8.62 xx 10^(-5) eV//K`) (300K) = 25.86 `xx 10^(-3) ` eV. Thus`(E )/(kT )= ( 2.1 eV )/( 25.86 xx 10^(-3)) = 81` The available thermal energy is nearly 81 times less than that of the required energy to CREATE electron hole pair. So it is difficult for the thermal energy to create the hole-electron pair but a PHOTON of light can do it easily. |
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