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The enhtaply change for the reaction of 50ml of ethylene with 50.0 mL if `H_(2)` at 1.5 atm pressure is `DeltaH=-0.31 KJ` . What is the `DeltaE`?A. `-0.3024`B. `0.6048`C. `0.1.2`D. None |
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Answer» Correct Answer - A `{:(C_(2)H_(4) ,"+", H_(2), rarr ,C_(2)H_(3)),(50ml, ,50ml,,o),(X,,X,,50ml):}` `DeltaH=DeltaU+P(DeltaV)` `-0.31=DeltaU + 1.5 xx 1.01 xx 10^(5) (-50 xx 10^(-6))`. `DeltaU=- 0.3024 KJ .` |
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