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The enthalpies of combustion of graphite and diamond are 393.5 kJ and 395.4 kJ respectively. Calculate the enthalp change accompanying the transformation of 1 mole of graphite into diamond. |
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Answer» Correct Answer - `1.9 kJ mol^(-1)` Given `: (i) C(gr) + O_(2)(g) rarr CO(_(2)(g), DeltaH = - 393. 5 kJ mol^(-1)` (ii) `C(dia) + O_(2)(g) rarr CO_(2)(g) , Delta H = -395kJ mol^(-1)` Aim `: C (gr) rarr C (dia) , Delta H = ?` Eqn. (i) - Eqn. (ii) gives the required result. |
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