InterviewSolution
Saved Bookmarks
| 1. |
The enthalpies of neutralization of HClO4and Cl3C – COOH are –13.5 kcal/g equivalent and –14.7 kcal/g equivalent respectively. When 40 gm of solid NaOH is added to a mixture of 1 gm mol HClO4and 1 g mol Cl3C – COOH, solution perchlorate and sodium trichloroacetate are formed in molar ratio of 3 : 1. Then(A)ΔH for the reaction of NaOH with the mixture is 6.45 kcal(B)ΔH for the reaction of NaOH with the mixture is 13.8 kcal(C) After reaction the total number of moles of acid remained are 0.5 (HClO4and Cl3C – COOH)(D) After reaction the total weight of acid remained is 147.75 gm (HClO4and Cl3C – COOH) andΔH for the reaction of NaOH with mixture is –13.8 kcal. |
|
Answer» Explanation (D) After reaction the total weight of acid remained is 147.75 gm (HClO4and Cl3C – COOH) andΔH for the reaction of NaOH with mixture is –13.8 kcal. Let x mole of NaOH are used in Ist reaction and (1–x) mol ofNaOH are used in 2nd reaction.
|
|