The enthalpy and entropy change for the reaction, `Br_(2)(l)+Cl_(2)(g)rarr2BrCl(g)` are `30KJmol^(-1)` and `105JK^(-1)mol^(-1)` respectively. The temperature at which the raction will be in equilibrium is:A. `450 K`B. `300 K`C. `285.7 K`D. `273 K`

The enthalpy and entropy change for the reaction, `Br_(2)(l)+Cl_(2)(g)

1.	The enthalpy and entropy change for the reaction, `Br_(2)(l)+Cl_(2)(g)rarr2BrCl(g)` are `30KJmol^(-1)` and `105JK^(-1)mol^(-1)` respectively. The temperature at which the raction will be in equilibrium is:A. `450 K`B. `300 K`C. `285.7 K`D. `273 K`
Answer» Correct Answer - C According to thermodynamics, `Delta G = Delta H - T Delta S` At equilibrium (by definition), `Delta G = 0`. Thus, ` 0 = Delta H - T Delta S` or `T = (Delta H)/(Delta S)` `= (30 xx 10^(3) J mol^(-1))/(105 J K^(-1) mol^(-1))` `285.7 K`

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The enthalpy and entropy change for the reaction, `Br_(2)(l)+Cl_(2)(g)rarr2BrCl(g)` are `30KJmol^(-1)` and `105JK^(-1)mol^(-1)` respectively. The temperature at which the raction will be in equilibrium is:A. `450 K`B. `300 K`C. `285.7 K`D. `273 K`

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