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The enthalpy and entropy changes for the reaction C(s) diamond `+ O_(2) rarr CO_(2)(g)` at `25^(@)C` and 1 atm. Are -393.4 kJ `mol^(-1)` and 0.006 `kJ mol^(-1)` respectively . Is the conversion of diamond to `CO_(2)` at room temperature a spontaneous process ? |
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Answer» Correct Answer - Yes `DeltaG = DeltaH - T DeltaS = -393.4kJ mol^(-1) - 298 K ( 0.006kJ K^(-1)mol^(-1) )= -ve.` |
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