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| 1. |
The enthalpy change `DeltaH` for the neutralisation fo `1M HCI` by caustic potash in dilute solution at `298 K` isA. 68kJB. 65 kJC. 57.3 kJD. 50 kJ |
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Answer» Correct Answer - C Since, both HCl and KOH are strong, 57.3 kJ heat will be released. |
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