1.

The enthalpy change `DeltaH` for the neutralisation fo `1M HCI` by caustic potash in dilute solution at `298 K` isA. 68kJB. 65 kJC. 57.3 kJD. 50 kJ

Answer» Correct Answer - C
Since, both HCl and KOH are strong, 57.3 kJ heat will be released.


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