The enthalpy change for the reaction of 5 litre of ethylene with 5 litre of `H_(2)` gas at 1.5 atm pressure is `Delta H= -0.5 kJ`. The value of `Delta U` will be: `( 1 atm Lt=100 J)`A. `-1.25 kJ`B. `+1.25 kJ`C. `0.25 kJ`D. `-0.25 kJ`

The enthalpy change for the reaction of 5 litre of ethylene with 5 lit

1.	The enthalpy change for the reaction of 5 litre of ethylene with 5 litre of `H_(2)` gas at 1.5 atm pressure is `Delta H= -0.5 kJ`. The value of `Delta U` will be: `( 1 atm Lt=100 J)`A. `-1.25 kJ`B. `+1.25 kJ`C. `0.25 kJ`D. `-0.25 kJ`
Answer» Correct Answer - C `CH_(2)H_(2)(g)+H_(2)(g) rarrC_(2)H_(4)(g)` `Delta H=Delta V+Deltan_(g)RT=Delta U+P Delta V` `-0.5=Delta U+1.5(-5)xx(100)/(1000)` `Delta U= -0.5+0.75` `Delta U= 0.25 kJ`

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The enthalpy change for the reaction of 5 litre of ethylene with 5 litre of `H_(2)` gas at 1.5 atm pressure is `Delta H= -0.5 kJ`. The value of `Delta U` will be: `( 1 atm Lt=100 J)`A. `-1.25 kJ`B. `+1.25 kJ`C. `0.25 kJ`D. `-0.25 kJ`

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