The enthalpy change for the reaction ,`Zn (s) + 2H^(+)(aq) rarr Zn^(2+) (aq)+ H_(2)(g)`, is `-154.0kJ mol^(-1)` . The formation of 2g of hydrogen expands the system by 22.4litresat1 atm pressure. What is the internal energy of the reaction ?

The enthalpy change for the reaction ,`Zn (s) + 2H^(+)(aq) rarr Zn^(2+

1.	The enthalpy change for the reaction ,`Zn (s) + 2H^(+)(aq) rarr Zn^(2+) (aq)+ H_(2)(g)`, is `-154.0kJ mol^(-1)` . The formation of 2g of hydrogen expands the system by 22.4litresat1 atm pressure. What is the internal energy of the reaction ?
Answer» Taking the initial volume as negligible ( as no gaseous reactant is present ) , change in volume during expansion `(DeltaV)= 22.4 l`.External pressure `( P_(ext)) =1atm`. `DeltaH = DeltaU + P DeltaV`or`DeltaU = DeltaH- P DeltaV` `P DeltaV= 1 atm xx22.4 L =22.4L` atm` = 22.4 xx101.3 J =2307J =2.31kJ` `:. DeltaU= - 154 .4- 2.31 = - 156.71 kJ`

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The enthalpy change for the reaction ,`Zn (s) + 2H^(+)(aq) rarr Zn^(2+) (aq)+ H_(2)(g)`, is `-154.0kJ mol^(-1)` . The formation of 2g of hydrogen expands the system by 22.4litresat1 atm pressure. What is the internal energy of the reaction ?

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