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The enthalpy change when 1 L of 1 M `H _(2)SO_(4)` is completely neutralized by 1L of1 M `Ca(OH)_(2)` will beA. `-13.7 kcal`B. `-27.4 kcal`C. `-1.37 kcal`D. `- 2.74 kcal` |
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Answer» Correct Answer - b 1 L of 1 M `H_(2)SO_(4)` gives 2 moles of`H^(+)` ions 1L of`M Ca9OH)_(2)` gives 2 moles of `OH^(-) ` ions Hence, for complete neutralization of 2 molesof `H^(+)` ions by 2 molesof `OH^(-)` ions. `DeltaH = 2 ( - 13.7) kcal =- 27.4 kcal` |
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