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the enthalpy of combustion of acetylene is -312 kCal per mole. If enthalpy of formation of `CO_(2)` & `H_(2)O` are `-94.38` & `-68.38` kCal per mole respectively, calculate `C equiv C` bond enthalpy. given that enthalpy of atomisation of C is 150 kCal per mole and `H-H` bond enthlpy and `C-H` bond enthalpy are 103 kcal per mole and 93.64 kCal per mole respectively. |
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Answer» Correct Answer - `E_(C equiv C)= 160.86` kCal/mol Enthalpy of formation of `C_(2)H_(2)=54.92` `2 C(s)+H_(2) rarr HC equiv C-H` `54.92=403-187.28-x" "[x=B.E." of "C equiv C]` `x=160.86" kCal/mol"` |
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