The enthalpy of combustion of ethyl alcohol `(C_(2)H_(5)OH)` is 1380.7 kJ `mol^(_1)`. If the enthalpies of formation of `CO_(2)` and `H_(2)O` are 394.5 and 286.6kJ `mol^(-1)` respectively, calculate the enthalpy of formation of ethyl alcohol.

The enthalpy of combustion of ethyl alcohol `(C_(2)H_(5)OH)` is 1380.7

1.	The enthalpy of combustion of ethyl alcohol `(C_(2)H_(5)OH)` is 1380.7 kJ `mol^(_1)`. If the enthalpies of formation of `CO_(2)` and `H_(2)O` are 394.5 and 286.6kJ `mol^(-1)` respectively, calculate the enthalpy of formation of ethyl alcohol.
Answer» Correct Answer - `-268.1kJ mol^(-1)` (i) `C_(2)H_(5)OH+ 3O_(2)rarr 2CO_(2)+3H_(2)O , DeltaH = - 1380.7 kJ mol^(-1)` (ii) `C+ O_(2) rarr CO_(2), DeltaH = - 394.5kJ mol^(-1)` (iii) `H_(2)+ (1)/(2)O_(2) rarr H_(2)O, DeltaH= - 286. 6 kJ mol^(-1)` We aim at `: 2C + 3H_(2)+ (1)/(2) O_(2) rarr C_(2)H_(5)OH` ` 2 xx `Eqn. (ii)`+ 3 xx ` Eqn. (iii) `-` Eqn. (i) gives the required result.

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The enthalpy of combustion of ethyl alcohol `(C_(2)H_(5)OH)` is 1380.7 kJ `mol^(_1)`. If the enthalpies of formation of `CO_(2)` and `H_(2)O` are 394.5 and 286.6kJ `mol^(-1)` respectively, calculate the enthalpy of formation of ethyl alcohol.

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