1.

The enthalpy of formation of ammonia is `- 46.2 mol^(-1)`. The enthalpy change for the reaction `2NH_(3) rarr N_(2) + 3 H_(2)` isA. `42.0 kJ`B. `64.0 kJ`C. `80.0 kJ`D. `92.0 kJ`

Answer» Correct Answer - D
`underset(2"moles")(2NH_(3))toN_(2)+3H_(2)`
The enthalpy of formation of ammonia
`=-46kJ mol^(-1)`
`DeltaH"of given reaction " =-2xx(-46)=92kJ`


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