InterviewSolution
Saved Bookmarks
| 1. |
The enthalpy of formation of enthane and benzene from the gaseous atoms are `-2839.2` and `-5506 kJ//mol` respectively. Bond enthalpy of `C = C` bond is Given: Resonance energy of benzene `=-23.68" kJ/mol"` Bond enthalpy of `C-H` bond `=411.0" kJ/mol"`A. 373.98 kJ/molB. 632.24 kJ/molC. 647.5 kJ/molD. 1896.72 kJ/mol |
|
Answer» Correct Answer - B `-2839.2=0-[6xx411+DeltaH_(C-C)]` `DeltaH_(C-C)=373.2" KJ/mol"` `6C(g) +6H(g) rarr C_(6)H_(6)(g)` `DeltaH_("theoritical")=0-[6xx411+3xx373.2+3x]` `R.E.="Actual"-"Theoritical"` `-23.68=-5506+[6xx411+3xx373.2+3x]` `3x=5506-23.68-2466-1119.6` `x=632.24" KJ/mol "`or`" "DeltaH_(C-C)=632.24" KJ/mol"` |
|