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The enthalpy of formation of ethane, ethylene and benzene from the gaseous atoms are -2839.2, -2275.2 and `-5506" kJ mol"^(-1)` respectively. Calculate the resonance energy of benzene. The bond enthalpy of `C-H` bond is given as equal to +410.87 kJ/mol. |
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Answer» Correct Answer - `-23.68` kJ/mol (i) `2C+6H rarr CH_(3)-CH_(3)" "DeltaH=-2839.2` `-2839.2=0-[(410.87xx6)]+C-C]` `C-C=373.98` (ii) `2C+4H rarr C_(2)H_(4)` `-22275.2=0-[1643.48+C=C]` `(C = C)=631.72` (iii) `6C+6H square rarr C_(6)H_(6)` `DeltaH_("calculayed")=5482.32` Resonance energy `=5482.32-5506=-23.68" kJ mol"^(-1)` |
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