1.

The enthalpy of fusion of water is`1.435kcal//mol`.The molar entropy change for the melting of ice at`0^(@)C`isA. 10.52 cal/mol KB. 21.04 cal/mol KC. 5.260 cal/mol KD. 0.526 cal/mol K

Answer» Correct Answer - C
Molar entropy change for the melting ice,
`DeltaS_("melt")=(DeltaH_("fussion"))/(T)=(1.435 kcal//"mol")/((0+273)K)`
`=526 xx 10^(-3)` kcal/mol K
=526 cal/mol K


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