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The enthalpy of neutralisation of HCl and NaOH is `-57KJmol^(-1)` .The heat evolved at constant pressure (in KJ when 0.5 mole of `H_(2)SO_(4)` reacts with 0.75 mole of NaOH is equal to :A. `57xx(3)/(4)`B. `57xx0.5`C. 57D. `57xx0.25` |
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Answer» Correct Answer - a |
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