InterviewSolution
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InterviewSolution
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The enthalpy of neutralisation of HCl by NaOH IS `-55.9 kJ ` and that of HCN by NaOH is `-12.1 kJ mol^(-1)`. The enthalpy of ionisation of HCN isA. `-43.8 KJ`B. `43.8 KJ`C. 68 KJD. `-68` KJ |
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Answer» Correct Answer - B `HCl+NaOH rarr NaCl + H_(2)O` OR `H^(+)+OH^(-)rarr H_(2)O , Delta H = -55.9 KJ mol^(-1)` …(i) `HCN+NaOHrarr NaCN+H_(2)O` OR `HCN+OH^(-)rarr CN^(-)+H_(2)O , Delta H=-121.1 KJ mol^(-1)` …(ii) `HCN rarr H^(+)+CN^(-) , Delta H = ?` eq(iii) = eq(ii) - eq(i) `Delta H_(3)=-12.1-(-55.9)=43.8 KJ` |
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