1.

The enthalpy of neutralization of `HNO_(3)` by `NaOH=-13680 cal//eqt.` When one equivalent of `NaOH` is added to a dilute solution containing one equivalent of `HNO_(3)` and one equivalent of a certain monoprotic weak acid `13960` cals are evolved. Assume that the base is distributed between `HNO_(3)` and the weak acid in the ratio `3:1` and the weak acid is practically nonionized. Calculate the enthalpy of ionization of the weak acid.A. `-1120` calsB. `-2110` calsC. `1210` calsD. `+1210 cals`

Answer» Correct Answer - 3
`13960=-13680xx(3)/(4)-13680xx(1)/(4)+(1)/(4)x`
where x is enthalpy of dissociation/ionisation of weak acid.
so `x=1120` calories.


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