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    				| 1. | The enthalpy of neutralization of `HNO_(3)` by `NaOH=-13680 cal//eqt.` When one equivalent of `NaOH` is added to a dilute solution containing one equivalent of `HNO_(3)` and one equivalent of a certain monoprotic weak acid `13960` cals are evolved. Assume that the base is distributed between `HNO_(3)` and the weak acid in the ratio `3:1` and the weak acid is practically nonionized. Calculate the enthalpy of ionization of the weak acid.A. `-1120` calsB. `-2110` calsC. `1210` calsD. `+1210 cals` | 
| Answer» Correct Answer - 3 `13960=-13680xx(3)/(4)-13680xx(1)/(4)+(1)/(4)x` where x is enthalpy of dissociation/ionisation of weak acid. so `x=1120` calories. | |