1.

The enthalpy of solution of sodium chloride is `4 kJ mol^(-1)` and its enthalpy of hydration of ions is ` -784 kJ mol^(-1)` . Then the lattice enthalpy of NaCl ( in `kJ mol^(-1))` isA. `+ 788`B. `+4`C. `+398`D. `+780`

Answer» Correct Answer - A
`DeltaH_("solution")=DeltaH _("lattice")+DeltaH_("hydration")+4= DeltaH _("lattice") +( -784)`
or `DeltaH _("lattice") =+ 788 kJmol^(-1)`


Discussion

No Comment Found

Related InterviewSolutions