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The enthalpy of solution of sodium chloride is `4 kJ mol^(-1)` and its enthalpy of hydration of ions is ` -784 kJ mol^(-1)` . Then the lattice enthalpy of NaCl ( in `kJ mol^(-1))` isA. `+ 788`B. `+4`C. `+398`D. `+780` |
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Answer» Correct Answer - A `DeltaH_("solution")=DeltaH _("lattice")+DeltaH_("hydration")+4= DeltaH _("lattice") +( -784)` or `DeltaH _("lattice") =+ 788 kJmol^(-1)` |
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