InterviewSolution
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InterviewSolution
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The enthaplpy changes state for the following processes are listed below: `Cl_(2)(g)=2Cl(g)` : `242.3KJmol^(-1)` `I_(2)(g)=2I(g)` , `151.0KJ mol^(-1)` `ICl(g)=I(g)+Cl(g)` : `211.3KJ mol^(-1)` `I_(2)(s)=l_(2)(g)` , `62.76KJ mol^(-1)` Given that the standard states for iodine chlorine are `I_(2)(s)` and `Cl_(2)(g)` , the standard enthalpy of formation for `ICl(g)` is:A. `+244.8KJmol^(-1)`B. `-14.6KJmol^(-1)`C. `-16.8KJmol^(-1)`D. `+16.8KJmol^(-1)` |
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Answer» Correct Answer - C `I_(2)+Cl_(2)rarr2ICl` `DeltaH=e_(I_(2)srarrg)+e_(I-I)+e_(Cl-Cl)-2xxe_(I-Cl)` `=62.76+151.0+242.3-2xx211.3` `=33.46KJ` for 2 moles of `ICl` :. `DeltaH//mol=(33.46)/(2)=16.73KJmol^(-1)` |
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