The Eo reduction for Cu/CuS electrode is −x. Find the value of x. (G – InterviewSolution

1.	The Eo reduction for Cu/CuS electrode is −x. Find the value of x. (Given: Ksp for CuS=8.0×10−36;Eo(Cu/Cu2+)=−0.34 V;log 2=0.3;2.303RTF=0.06)
Answer» The $E^{o}$ reduction for $C u / C u S$ electrode is $- x$ . Find the value of $x$ . (Given: $K_{s p}$ for $C u S = 8.0 \times 10^{- 36}; E_{(C u / C u^{2 +})}^{o} = - 0.34 V; l o g 2 = 0.3; \frac{2.303 R T}{F} = 0.06$ )

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