1.

The equal resistances, 400 Omega each are connected in series with a 8V battery. IF the resistance of first one increases by 0.5%, the charge required in the resistance of the second one in order to keep the potential difference across it unaltered is to

Answer»

increase it by `1 OMEGA`
increase it by `2 Omega`
increase it by `4 Omega`
decrease it by `4 Omega`

Solution :Increase in first resistance=`400 times 0.5/100=2 Omega`
Initially, the emf 8V will be divided equally between the two resistances.SO the voltage across each resistance will be 4V. When the first resistance is INCREASED, the second resistance should also be inceased by `2 Omega` to KEEP the voltage across it unchanged.


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