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The equation of a damped simple harmonic motion is `m(d^2x)/(dt^2)+b(dx)/(dt)+kx=0`. Then the angular frequency of oscillation isA. `omega=(k/m-(b^2)/(4m^2))^(1//2)`B. `omega=(k/m-(b)/(4m))^(1//2)`C. `omega=(k/m-(b^2)/(4m))^(1//2)`D. `omega=(k/m-(b^2)/(4m^2))^(1//2)` |
Answer» Correct Answer - A `omega=sqrt(k/m-((b)/(2m))^2)` |
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