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The equation of a damped simple harmonic motion is `m(d^2x)/(dt^2)+b(dx)/(dt)+kx=0`. Then the angular frequency of oscillation isA. `omega=((k)/(m)-(b^(2))/(4m^(2)))^(1//2)`B. `omega=((k)/(m)-(b)/(4m))^(1//2)`C. `omega=((k)/(m)-(b^(2))/(4m))^(1//2)`D. `omega=((k)/(m)-(b^(2))/(4m^(2)))^(-1//2)` |
Answer» Correct Answer - A (a)`omega=sqrt((k)/(m)-((b)/(2m))^(2))` |
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