1.

The equation of a line passing through (1,-1,0) and parallel to `(x-2)/3=(2y+1)/2=(5-z)/(-1)` isA. `(x-1)/3=(y+1)/3=(z-0)/(-1)`B. `(x-1)/3=(y+1)/1=(z-0)/(-1)`C. `(x-1)/3=(y+1)/1=(z-0)/1`D. `(x-1)/3=(y+1)/2=(z-0)/1`

Answer» Correct Answer - C
The equation of the give line can be are written as
`(x-2)/3=(y+1//2)/1=(z-5)/1`
Clearly, its direction ratios are proportional to 3,1,1. So direction ratios of parallel line are also proportional to 3,1,1. Hence the equation of the required line is `(x-1)/3=(y+1)/1=(z-0)/1`


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