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The equation of a line passing through the points (3.-2) and inclined at an angle of 45 degree with the positive direction of X -axis is |
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Answer» -step EXPLANATION:inclination = 45°slope (m) = tan 45° = 1taking point (3,-2) as (x1, Y1)the equation of the required LINE:=> y - y1 = m( x - x1) => y - (-2) = 1 ( x - 3)=> y + 2 = x - 3=> x - y = 5 |
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