The equation of a particle executing `SHM` is `(d^(2)x)/(dt^(2))=-omega^(2)x`. Where `omega=(2pi)/("time period")`. The velocity of particle is maximum when it passes through mean position and its accleration is maximum at extremeposition. The displacement of particle is given by `x=A sin(omegat+theta)` where `theta`-initial phase of motion. `A`-Amplitude of motion and T-Time period The accleration is half of its maximum value at an amplitude ofA. `(A)/(sqrt2)`B. `(sqrt3A)/(2)`C. `(A)/(sqrt3)`D. `(A)/(2)`

The equation of a particle executing `SHM` is `(d^(2)x)/(dt^(2))=-omeg

1.	The equation of a particle executing `SHM` is `(d^(2)x)/(dt^(2))=-omega^(2)x`. Where `omega=(2pi)/("time period")`. The velocity of particle is maximum when it passes through mean position and its accleration is maximum at extremeposition. The displacement of particle is given by `x=A sin(omegat+theta)` where `theta`-initial phase of motion. `A`-Amplitude of motion and T-Time period The accleration is half of its maximum value at an amplitude ofA. `(A)/(sqrt2)`B. `(sqrt3A)/(2)`C. `(A)/(sqrt3)`D. `(A)/(2)`
Answer» Correct Answer - D

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