1.

The equation of a progressive wave isy = 4 sin (4pit - 0.04 x + pi/3)where x is in meter and t is in second. The velocity of the wave is

Answer»

`100 PI m//s`
`50 pi m//s`
`25 pi m//s`
`pi m//s`

SOLUTION :The given wave equation is
`y = 4 SIN(4pi t- 0.04 x + pi/3)`
Compare it with the standard wave EQUTION
`y =A sin(omega t - kx + phi)`
we get, `omega = 4pi rad s^(-1), k= 0.04 rad m^(-1)`
`therefore` Velocity of the wave, `v = omega/k = (4pi rad s^(-1))/(0.04 rad m^(-1)) = 100 pi ms^(-1)`


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