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The equation of a travelling wave is `y60 cos(1800t-6x)` where y is in microns, t in seconds and x in metres. The ratio of maximum particle velocity to velocity of wave propagation isA. 3.6B. `3.6xx10^(-6)`C. `36xx10^(-11)`D. `3.6xx10^(-4)` |
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Answer» Correct Answer - d Maximum particle velocity =`omegaA` wave velocity =`(omega)/(K)` Therefore, the required ratio `=(omegaA)/(omega//K)` `AK` `=60xx10^(-6)xx6` `=3.6xx10^(-4)` |
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