1.

The equation of a travelling wave is `y60 cos(1800t-6x)` where y is in microns, t in seconds and x in metres. The ratio of maximum particle velocity to velocity of wave propagation isA. 3.6B. `3.6xx10^(-6)`C. `36xx10^(-11)`D. `3.6xx10^(-4)`

Answer» Correct Answer - d
Maximum particle velocity =`omegaA`
wave velocity =`(omega)/(K)`
Therefore, the required ratio
`=(omegaA)/(omega//K)`
`AK`
`=60xx10^(-6)xx6`
`=3.6xx10^(-4)`


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