1.

The equation of an alternating current is `I = 50 sqrt(2) sin 400 pi t A`, then the frequency and the root mean square value of current are respectively.A. `200 Hz, 50 A`B. `400 Hz, 50 sqrt(2) A`C. `200 Hz, 50 sqrt(2) A`D. `500 Hz, 200 A`

Answer» Correct Answer - 1
`I = 50 sqrt(2) sin 400 pi t`, `l = l_(0) sin omega t`
Comparing two equation, we get
`omega = 2 pi f = 400 pi , f = 200 Hz`
and `I_(0) = 50 sqrt(2)`
`I_("rms") = (I_(0))/(sqrt(2)) = 50 A`


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