The equation of perpendicular bisector of the line segment joining the

1.	The equation of perpendicular bisector of the line segment joining the point (1,2) and (-2,0) is:
Answer» Let `AB` is the line segment joining the point `(1,2) and (-2,0)` and `C` is the midpoint og `AB`. The, coordinates of `C` will be `(-1/2,1)`. Slope of `AB, m_(AB) = (0-2)/(-2-1) = 2/3` Now, let `CL` is the perpendicular bisector of `AB`. Then, `m_(CL)m_(AB) = -1` (Here, `m_(CL)` is slope of `CL`) `m_(CL)2/3 = -1=> m_(CL) = -3/2` Now, we know the slope and coordinates of point C. So, the equation will be, `y-1 = -3/2(x+1/2) = > 4y-4 = -6x -3` `=>6x+4y-1 = 0`

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The equation of perpendicular bisector of the line segment joining the point (1,2) and (-2,0) is:

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