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The equation of plane passing through the point `hati+hatj+hatk` and paralel to the plane `vecr.(2hati-hatj+2hatk)=5` isA. `vecr.(2hati-hatj+2hatk)=5`B. `vecr.(2hati-hatj+2hatk)=-3`C. `vecr.(2hati-hatj+2hatk)=3`D. none of these |
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Answer» Correct Answer - C The equation of a plane parallel to the plane `vecr.(2hati-hatj+2hatk)=5` is `vecr.(2hati-hatj+2hatk)=d`…………….i Since it passes through `hati+hatj+hatk`. `:.(hati+hatj+hatk).(2hati-hatj+2hatk)=dimplies2-1+2=d=d=3`. Putting `d=3` in i we obtain `vecr.(2hati-hatj+2hatk)=3` This is the equation of the required plane. |
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