1.

The equation of plane passing through the point `hati+hatj+hatk` and paralel to the plane `vecr.(2hati-hatj+2hatk)=5` isA. `vecr.(2hati-hatj+2hatk)=5`B. `vecr.(2hati-hatj+2hatk)=-3`C. `vecr.(2hati-hatj+2hatk)=3`D. none of these

Answer» Correct Answer - C
The equation of a plane parallel to the plane `vecr.(2hati-hatj+2hatk)=5` is
`vecr.(2hati-hatj+2hatk)=d`…………….i
Since it passes through `hati+hatj+hatk`.
`:.(hati+hatj+hatk).(2hati-hatj+2hatk)=dimplies2-1+2=d=d=3`.
Putting `d=3` in i we obtain `vecr.(2hati-hatj+2hatk)=3`
This is the equation of the required plane.


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