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The equation of projectile is y=sqrt(3)-g/2x^(2) , the angle of its projection is : |
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Answer» `pi/2` `y=xtantheta -(G/(2u^(2)cos^(2)theta)).x^(2)`compairing this with `y=sqrt(3x)-g x^(2)/2` we have `tantheta=sqrt(3)` |
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