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The equation of resultant wave due to the two waves is y' (x, t) |
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Answer» `2ym (sinphi)[sin(kx - OMEGAT + PHI)]` `y_(2) = y_(m) sin(kx - omegat + phi)` Resultant is OBTAINED by superposition `y' = y_(1) + y_(2)` = `y_(m)[2sin(kx - omegat + (phi)/(2))cos((phi)/(2))]` |
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