1.

The equation of resultant wave due to the two waves is y' (x, t)

Answer»

`2ym (sinphi)[sin(kx - OMEGAT + PHI)]`
`y_(m)(sinphi) [sin(kx - omegat + (phi)/(2))]`
`2y_(m)(cos"(phi)/(2))[sin(kx - omegat +(phi)/2)]`
`2y_(m)(cosphi)[sin(kx -omegat + phi)]`

SOLUTION :`y_(1) = y_(m) sin(kx - omegat)`
`y_(2) = y_(m) sin(kx - omegat + phi)`
Resultant is OBTAINED by superposition
`y' = y_(1) + y_(2)`
= `y_(m)[2sin(kx - omegat + (phi)/(2))cos((phi)/(2))]`


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